1351C - Skier - CodeForces Solution


data structures implementation *1400

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Python Code:

from collections import defaultdict


def walk(x,y,d) :
	if d == "N" :y+=1
	if d == "S" :y-=1
	if d == "E" :x+=1
	if d == "W" :x-=1
	return (x,y)

def opposite(d):
	if d == "N" :return "S"
	if d == "S" :return "N"
	if d == "E" :return "W"
	if d == "W" :return "E"


R = lambda: map(int, input().split())
L = lambda: list(R())
for _ in range(int(input())):
	d = defaultdict(set)
	x, y = 0, 0
	ans = 0
	s = input()
	for i in s :
		if i in d[(x,y)] : ans+=1
		else :
			d[(x,y)].add(i)
			ans+=5
		x,y = walk(x,y,i)
		d[(x,y)].add(opposite(i))
	print(ans)

C++ Code:

#include <bits/stdc++.h>
using namespace std;
 
int main(){
	int t;
	cin >> t;
	while(t--){
    string s;
	cin >> s;
	set<pair<int,int>> se;
	int g=0,d=0,p,h;
	int ans=0;
	for(auto c: s){
		p=d;h=g;
		if(c=='N')g++;
		else if(c=='S')g--;
		else if(c=='W')d--;
		else d++;
		if(!se.count({p+d,h+g})){
			ans+=5;
			se.insert({p+d,h+g});
		}else ans++;
	}
	cout<<ans<<endl;
	}
	return 0;
}


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